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Q1. Two isolated spherical conductors having radii 5 cm and 10 cm. They have charges of 12nC and -3nC respectively. Find the charges after they are connected by a conducting wire. Also, find the common potential after redistribution. Ans. 3 nC,  6 nC,  540V Q2. Two parallel plate capacitors A and B having capacitance of 1μF and 5 μF are charged separately to the same potential of 100V. Now, the positive plate of A is connected to the negative plate of B, and the negative plate of A is connected to the positive plate of B. Find the final charges on each capacitor. Ans. (200/3 μC),  (1000/3) μC This is the video for the Lovely students CLICK HERE by    www.advguruji.blogspot.com

Consider, an electric dipole of length 2a having charges +q and -q . A point P is at a distance r from the centre of the dipole such that OP is making an angle θ with dipole moment p . CONSTRUCTION :- Extend OP to BP such that BC is perpendicular to BP, Draw AD perpendicular to BP. PROOF :- Now, β = r + aCosθ      .........(1)          α = r + aCosθ      .........(2) Let, 'V1' and 'V2' be the potential due to +q and -q respectively. Net electric potential at 'P' is -               V = V1 + V2             V = kq/α + k(-q)/β             From equation (1) and (2)            Also,       p = q.2a Therefore,               [  V = kpCosθ/(r² - a²Cos²θ)   ] Note :- For axial line, θ = 0           For equatorial line, θ = π/2 Pyaare bacchon, tumhari help k liye video daali hai by  www.advguruji.blogspot.com

Q1. The sum of two digit number and the number obtained by reversing the order of its digits is 121, and the two digits differ by 3. Find the number. Answer.    47 or 74 Q2. The sum of the digits of a two digit number is 9. Also, nine times this number is twice the number obtained by reversing the order of the digits. Find the number. Answer.    18 Q3. When a two digit number and its reverse order digit number are added, the result is 99. The tens digit of the number is greater to the ones digit by 5. Find the number. Answer.  72 LOVELY STUDENTS... PLEASE COMMENT IF YOU HAVE ANY DOUBT               by    www.advguruji.blogspot.com