Consider, an uniformly charged infinite sheet having surface charge density σ . Let, A be the small area of the sheet containing charge q . As, charge lie on both the sides of the sheet, so electric field E is also on both the sides. using Gauss theorem, net electric flux through the cylinder enclosing the charge 'q' is - Φ = q/εο ......(1) But, Φ = Φ1 + Φ2 + Φ3 = EACos0° + EACos0° + 0 Φ = 2EA .......(2) From equation (1) & (2) 2EA = q/εο ...
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