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Electric field near an uniformly charged infinite sheet | class 12 physics | advguruji

Consider, an uniformly charged infinite sheet having surface charge density σ.

Let, A be the small area of the sheet containing charge q.
As, charge lie on both the sides of the sheet, so electric field E is also on both the sides.
using Gauss theorem, net electric flux through the cylinder enclosing the charge 'q' is -

                      Φ    =  q/εο          ......(1)

But,                Φ   =  Φ1 + Φ2 + Φ3
                            = EACos0° + EACos0° + 0

                       Î¦  =  2EA      .......(2)

          From equation (1) & (2)
                2EA = q/εο
                 E    =   q/2Aεο

 Also,          σ  = q/A
 Therefore,    
                 [  E = σ/2εο  ]


Still not clear


    by   www.advguruji.blogspot.com

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