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Age problems (for practice) | class 10 mathematics | advguruji | Physics Advocate

Linear Equations

Q1.
Ten years ago, father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be. Find their present ages.
Ans. Present age of father = 34 years
         Present age of son = 12 years


Q2.
Three years ago, Priya's mother was six times older than her. Four years from now, Priya's mother will be one year older than thrice her age. Find the present age of Priya and her mother.
Ans. Present age of Priya = 8 years
      Present age of mother = 33 years


Q3.
Five years ago, Rakesh was five times younger than his mother. Ten years from now, his age will be half of his mother's age. Find the present age of Rakesh and his mother.
Ans. Present age of Rakesh = 10 years
     Present age of mother = 30 years


Q4.          (equation in one variable)
A is elder to B by two years. A's father F is twice as old as A. B is twice as old as his sister S. If the ages of the father and sister differ by 40 years, find the age of A.
Ans. 26 years
Comment down your thoughts :-)
For "fraction based problems"


BEST OF LUCK.. to my dear students..

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