Skip to main content

Electricity, class 10 science, extra questions by Physics Advocate | advguruji

Electricity - Extra questions

Q1. Find the heat generated in a wire of resistance 100Ω connected to a constant voltage supply of 80 volts for 15 seconds.

Q2. An electric iron of rating 200V, 4A is connected to a suitable 200V voltage source. If a fan with power consumption 100W is connected to the iron with an independent switch. Calculate -
(i) Current for the entire circuit.
(ii) Resistance of the entire circuit.

Q3. Find the resistivity of a wire with resistance 200Ω, length 2 m and having cross-sectional area 2.5 mm².

Q4. Which has more resistivity : a thin copper wire at 30°C or a thick copper wire at 30°C?

Q5. Which has more resistivity : a copper wire at 30°C or an aluminium wire at 30°C?

Q6. Which has more resistivity : a copper wire at 30°C or a copper wire at 42°C with same length and diameter?

Q7. Calculate the resistance of a wire with resistivity 2 × 10-⁶ Ωm, length 5 m and diameter 2 mm. Take, π = 3.14

Q8. How many 10 Ohms resistors are required to make an equivalent resistance of -
(i) 5 Ω
(ii) 1.25 Ω
(iii) 20 Ω
(iv) 15 Ω
(v) 25 Ω
(vi) 22.5 Ω
Comment down your thoughts :⁠-⁠)

by www.advguruji.blogspot.com
----------------------------------------
Answers

Ans1. 960 J
Ans2. (i) 4.5 A    (ii) 44.44 Ω
Ans3.  2.5 × 10-⁴ Ωm
Ans4. Both have same resistivity
Ans7. 3.18 Ω
Ans8. (i) 2   (ii) 8   (iii) 2
(iv) 3   (v) 4   (vi) 6
Labels:

Comments

Post a Comment

Popular posts from this blog

Age problems (for practice) | class 10 mathematics | advguruji | Physics Advocate

Linear Equations Q1. Ten years ago, father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be. Find their present ages. Ans. Present age of father = 34 years          Present age of son = 12 years Q2. Three years ago, Priya's mother was six times older than her. Four years from now, Priya's mother will be one year older than thrice her age. Find the present age of Priya and her mother. Ans.  Present age of Priya = 8 years       Present age of mother = 33 years Q3. Five years ago, Rakesh was five times younger than his mother. Ten years from now, his age will be half of his mother's age. Find the present age of Rakesh and his mother. Ans. Present age of Rakesh = 10 years      Present age of mother = 30 years Q4.           (equation in one variable) A  is elder to  B  by two years. A's father  F  is twice as old as  A .  ...
1 comment
Read more

Problems on acceleration due to gravity and variation of acceleration due to gravity, class 11 | Physics Advocate

Q1. Calculate the percentage decrease in the weight of a body when it is taken to a height of 40 km above the Earth's surface. Radius of Earth = 6,400 km Ans. 1.25% Q2. Calculate the depth below the surface of Earth where the acceleration due to gravity is 25% of its value at the Earth's surface. Take, radius of Earth = 6,400 km. Ans. 4.8 × 10⁶ m Q3. A body weighs 100N on Earth's surface. Calculate the gravitational force on the body at a height equal to one-fourth the radius of Earth. Ans. 64 N Q4. Calculate the percentage decrease in weight of a body when taken to a tunnel 38.4 km below the Earth's surface. Ans. 0.6% Q5. Calculate the height from the Earth's surface at which the acceleration due to gravity becomes 75% compared at Earth's surface. Take, radius of Earth = 6,400 km. Ans. 990 km ---------------------------------------------------------------------------------------------- EXTRA QUESTIONS Q6. Find the percentage increase in acceleration due to grav...
Post a Comment
Read more

Energy of electron in nth orbit of Hydrogen atom | Numericals by Physics Advocate

Q1. How much energy is needed to relocate an electron from first excited state to fourth excited state in an Hydrogen atom? Also, find the type of light needed in this process. Q2. Find the wavelength of light released when an electron jumped from 4th excited state to ground state in an Hydrogen atom. Also, name the series. Q3. Find the wavenumber of light released when an electron jumped from 5th excited state in bracket series (in H - atom). www.advguruji.blogspot.com Q4. An electron absorbed 2.55 eV energy and jumped from first excited state to nth excited state. Find n . Q5. when an electron jumped from second excited state to some different state, UV ray was released. Name the state and find the frequency of the UV ray. --------------------------------------------------------------------------------------------------- ANSWERS Ans1. 2.86 eV Ans2. 99 nm Ans3. 0.375 × 10⁶ m-¹ Ans4. n = 3 Ans5. 2.90 × 10¹⁵ Hz by    www.advguruji.blogspot.com
Post a Comment
Read more