Skip to main content

Stefan's law, emissivity, emissive power - explanation by advguruji/Physics Advocate

Stefan's law
All objects radiate energy continuously in the form of electromagnetic waves. The rate at which an object radiates energy is proportional to the fourth power of its absolute temperature. This is known as the Stefan's law and is expressed in equation form as -

[   I = σeT⁴   ]
Here I is the intensity of radiation in W/m² radiated by the object, T is the absolute temperature in kelvin (K), e is a fraction between 0 and 1 called the emissivity of the object and σ is a universal constant called Stefan's constant, which has the value -

σ = 5.67 × 10-⁸ W/m²/K⁴
This law is also known as Stefan-Boltzmann law.

Confusion in emissivity (e) ?
I can explain-

Emissivity
The ratio of emissive power (E) of a body to the emissive power (ε) of a black body (a body that absorbs all the radiations falling on it) at same temperature is called emissivity. It is denoted by e.
Thus, emissivity -
          [ e = E/ε ]
It is a dimensionless quantity.
(i) For highly polished body, e = 0
(ii) For practical bodies, 0 < e < 1

Note :- Emissive power is basically the intensity of radiation emitted by a body.

Comment down your thoughts :-)

by
www.advguruji.blogspot.com

Comments

Popular posts from this blog

Age problems (for practice) | class 10 mathematics | advguruji | Physics Advocate

Linear Equations Q1. Ten years ago, father was twelve times as old as his son and ten years hence, he will be twice as old as his son will be. Find their present ages. Ans. Present age of father = 34 years          Present age of son = 12 years Q2. Three years ago, Priya's mother was six times older than her. Four years from now, Priya's mother will be one year older than thrice her age. Find the present age of Priya and her mother. Ans.  Present age of Priya = 8 years       Present age of mother = 33 years Q3. Five years ago, Rakesh was five times younger than his mother. Ten years from now, his age will be half of his mother's age. Find the present age of Rakesh and his mother. Ans. Present age of Rakesh = 10 years      Present age of mother = 30 years Q4.           (equation in one variable) A  is elder to  B  by two years. A's father  F  is twice as old as  A .  ...

Multiple Choice Questions (MCQs) on fluid mechanics class 11 : Physics advocate/advguruji

Best of Luck Q1. Hairs of shaving brush cling together when it is removed from water due to- (a) force of attraction between hair (b) surface tension (c) viscosity of water (d) characteristic property of hair Q2. Coatings used on raincoat are waterproof because they - (a) increases angle of contact (b) decreases angle of contact (c) does not alters angle of contact (d) forms a smooth surface Q3. A body measures 5 N in air and 2 N when put in water. The buoyant force is- (a) 7 N (b) 9 N (c) 3 N (d) None of these Q4. A hole is made at the bottom of the tank filled with water (density = 1000 kg/m³). If the total pressure at the bottom of the tank is three atmospheres (1 atmosphere = 10⁵ N/m²), then the velocity of efflux is nearest to- (a) 20 m/s (b) 10√2 m/s (c) 20√2 m/s (d) √500 m/s Q5. When the temperature is increased the angle of contact of a liquid? (a) increases (b) decreases (c) remains the same (d) first increases and then decreases Q6. The surface tension of a soap solution is 2...

Problems on acceleration due to gravity and variation of acceleration due to gravity, class 11 | Physics Advocate

Q1. Calculate the percentage decrease in the weight of a body when it is taken to a height of 40 km above the Earth's surface. Radius of Earth = 6,400 km Ans. 1.25% Q2. Calculate the depth below the surface of Earth where the acceleration due to gravity is 25% of its value at the Earth's surface. Take, radius of Earth = 6,400 km. Ans. 4.8 × 10⁶ m Q3. A body weighs 100N on Earth's surface. Calculate the gravitational force on the body at a height equal to one-fourth the radius of Earth. Ans. 64 N Q4. Calculate the percentage decrease in weight of a body when taken to a tunnel 38.4 km below the Earth's surface. Ans. 0.6% Q5. Calculate the height from the Earth's surface at which the acceleration due to gravity becomes 75% compared at Earth's surface. Take, radius of Earth = 6,400 km. Ans. 990 km ---------------------------------------------------------------------------------------------- EXTRA QUESTIONS Q6. Find the percentage increase in acceleration due to grav...